Use Calculator to calculate the Molarity of concentrated acetic acid (CH3COOH) when concentration is given in % by mass (w/w) Therefore, we can say that 1 liter of glacial acetic acid contains 17.416 moles or in other words molarity of glacial acetic acid (99.7% w/w, density 1.049 g/ml) is equal to 17.416. This means 17.416 moles of CH3COOH is present in 1000 ml of Glacial acetic acid. Step 3: Calculate the number of moles of acetic acid present in 1045.85 grams of acetic acid.ġ g r a m o f a c e t i c a c i d = 1 60. Which compound has the higher boiling pointbutanoic acid (molar mass 88) or 2-pentanone (molar mass 86) Explain.
Note: Since the volume of 1049 g of Glacial acetic acid is 1000 ml, we can say that 1045.85 g of CH3COOH is present in 1000 ml of Glacial acetic acid. acetic acid: 17: 118: miscible: CH 3 CH 2 COOH: propionic acid 22: 141: miscible: CH 3 (CH 2) 2 COOH: butyric acid 5: 163: miscible: CH 3 (CH 2) 3 COOH: valeric. Step 2: Calculate how much CH 3 COOH is in 1049 g of Glacial acetic acid.ġ00 g Glacial acetic acid contains: 99.7 g of CH3COOHġ g Glacial acetic acid will contain: 99.7/100 g of CH3COOHġ049 g Glacial acetic acid will contain: 1049 x 99.7/ 100 = 1045.85 g of CH3COOH Weight of 1000 ml Glacial acetic acid is 1049 g. Step 1: Since molarity refers to number of moles in 1000 ml solution, calculate the weight of 1000 ml Glacial acetic acid using the following formula: Molarity refers to the number of moles of the solute present in 1 liter of solution. The density of glacial acetic acid is 1.049 g/ml at 25☌ which means that the weight of the 1 ml of glacial acetic acid is 1.049 grams at 25☌. A 99.7% (w/w) glacial acetic acid means that 100 g of glacial acetic acid contains 99.7 g of acetic acid. A 99.7% (w/w) concentrated glacial acetic acid can be obtained from different suppliers. Glacial acetic acid is a clear colorless liquid.
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